**Balmer’s series** lies in the region of the spectrum called a visible region. The series of spectral lines produced due to transitions from all energy states to energy states E_{2} is called Balmer’s series.

For Balmer’s series P=2 and n=3,4,5,6,7………∞

Wavelength in Balmer’s series of H-atom,

1/λ = R [1/p^{2} – 1/n^{2} ]

R is Rydberg constant, the value of rydberg constant is **10,973,731.5682 per meter** or **1.097×10 ^{7}/m**

1/λ = 1.097×10^{7} [1/p^{2} – 1/n^{2} ] m^{-1}

For shorter wavelength in Balmer’s series,

p=2 and n=∞

1/λ_{min} = 1.097×10^{7} [1/2^{2} – 1/ ∞ ^{2} ] m^{-1}

1/λ_{min} = 1.097×10^{7} [1/4] m^{-1}

λ_{min} = 4/ 1.097×10^{7} m

λ_{min} = 3.646×10^{-7} m

λ_{min} = 364.6×10^{-9} m

**λ _{min} = 364.6 nm**

## Bohr’s atomic model:

Basically, Bohr presents his model to understand the atomic structure. Before the Bohr model, the plum pudding model is also present. The Plum pudding model fails to explain the atomic structure.

Rutherford’s model is based upon classical electromagnetic theory. Although, Rutherford’s experiments proved that the Plum pudding model of an atom was not correct. Yet it has the following defects:

### Defect’s of Rutherford’s model:

- According to the classical theory of radiation, electrons being the charged particles should release or emit energy continuously and they should ultimately fall into the nucleus.
- If the electron emits energy continuously, it should form a continuous spectrum but in fact, the line spectrum was observed.

According to classical electromagnetic theory, there is a center of positive charge in an atom which is called **the nucleus** and electrons is revolving around the nucleus. According to classical electromagnetic wave theory, the electrons that revolve in the orbit are accelerated. (every point the direction of velocity is changed)

In electricity and magnetism, when the charged particle is accelerated, they produce electromagnetic radiations. so, according to Rutherford’s the electrons that continuously revolve are accelerated and the energy of electrons is deceased that’s why electrons emit energy continuously** and fall in the nucleus**.

Keeping in view the defects of Rutherford’s atomic model. **Niels Bohr** presented another model of the atom in **1931.** The Quantum theory of Max Planck was used as the foundation of this model. According to Niel’s Bohr, a revolving electron in an atom does not absorb or emit energy continuously. The energy of revolving electrons is quantized as it revolves only in orbits of fixed energy called energy levels or **shells.**

### Postulates of Bohr atomic model:

- The hydrogen atom consists of a tiny nucleus and electrons are revolving in one of the circular orbits of radius ”r” around the nucleus.
- Each orbit has fixed energy that is quantized.
- Electrons remain in particular orbits, it does not radiate or emits energy. The energy is emitted or absorbed only when an electron jumps from one orbit to another.
- When an electron jumps from lower orbit to higher orbit, it absorbs energy and when it jumps from a higher orbit to lower orbit, it released energy.

*Energy is not continuous, energy is quantized*5. Electron can revolve only in orbits of a fixed angular momentum mvr,

mvr = n×h/2π

where n is the Quantum number having values 1,2,3…so on.

## Derivation of Bohr’s Model:

A hydrogen atom has one proton in the nucleus and only one electron is revolving around it. The ionization energy of hydrogen is 13.6 ev. Suppose electron is revolving with speed ”v” in an orbit of radius ”r”

The column force of attraction between electron and proton provides electron to required centripetal force to revolve around the nucleus. Thus,

F_{coloumb} = F_{centripital}

- F
_{coloumb}= k×q_{1}q_{2}/r^{2}or k×Ze × e /r^{2} - F
_{centripetal}= mv^{2}/r - k = 1/4πϵ
_{°}

1/4πϵ_{°}. Ze × e /r^{2} = mv^{2} /r

1/4πϵ_{°}. Ze^{2} /r^{2} = mv^{2} /r

v^{2} = Ze^{2} r / 4πϵ_{°} r^{2} m

v^{2} = Ze^{2} / 4πϵ_{°} mr

v = √ Ze^{2} / 4πϵ_{°} mr ——– (1)

### Frequency of revolution:

As,

v = rω

v = r(2πf)

v = 2πrf

f = 1/2πr × v

put the value of v from (1)

f = 1/2πr × √ Ze^{2} / 4πϵ_{°} r m

f = √1/4π^{2}r^{2} × √ Ze^{2} / 4πϵ_{°} r m

f = √Ze^{2}/ 16 π^{3}ϵ_{°}mr^{3} ——– (2)

### Total energy:

E = K.E + P.E ——–(A)

- K.E = 1/2 × mv
^{2}

put the value of v from (1)

K.E = 1/2 × m [√ Ze^{2} / 4πϵ_{°} mr ]^{2}

K.E = 1/2 × m [ Ze^{2} / 4πϵ_{°} mr ]

K.E = m/2 × [ Ze^{2} / 4πϵ_{°} mr ]

K.E = Ze^{2} / 8πϵ_{°} r ——– (B)

- P.E = Potential difference × charge of e
^{−}

∴ v = ω/q

ω = vq

∴ v = 1/4πϵ_{°} × q/r

P.E = 1/4πϵ_{°} . Ze/r × (−e)

P.E = −1/4πϵ_{°} . Ze^{2}/r ——– (C)

Put (B) and (C) in (A)

E = Ze^{2} / 8πϵ_{°} r × ( −1/4πϵ_{°} . Ze^{2}/r )

E = Ze^{2} − 2Ze^{2} / 8πϵ_{°} r

E =−Ze^{2} / 8πϵ_{°} r ——– (3)

### Angular momentum:

L = r × p

L = r × (mv)

L = mvr sinθ

∴ θ = 90^{°}

L = mvr

put the value of v from (1)

L = mr × √ Ze^{2} / 4πϵ_{°} r m

L = √ m^{2}r^{2} × √ Ze^{2} / 4πϵ_{°} mr

L = √ Ze^{2} m^{2}r^{2} / 4πϵ_{°} mr

L = √ Ze^{2} mr / 4πϵ_{°} ——–(4)

### Relation between frequency and energy:

From eq. (3)

E =−Ze^{2} / 8πϵ_{°} r

r =−Ze^{2} / 8πϵ_{°} E

From eq. (2)

f = √Ze^{2}/ 16 π^{3}ϵ_{°}mr^{3}

put the value of ”r”

f = √Ze^{2}/ 16 π^{3}ϵ_{°}m ( −Ze^{2} / 8πϵ_{°} E )^{3}

f = √Ze^{2}/ 16 π^{3}ϵ_{°}m ( −Z^{3}e^{6} / 512π^{3}ϵ_{°}^{3} E^{3} )

f = √512 π^{3}ϵ_{°}^{3} E^{3} . Ze^{2}/ 16 π^{3}ϵ_{°}m. −Z^{3}e^{6}

f = √−32 ϵ_{°}^{2} E^{3} / Z^{2} m e^{4}

eq. (5) derived classically so,

f_{cm} = (−32 ϵ_{°}^{2} E^{3} / Z^{2} m e^{4} )^{1/2} ——– (5)

For large Quantum number,

put E = −hcR/n^{2} in (5)

f_{cm} = (−32 ϵ_{°}^{2} / Z^{2} m e^{4} × ( −hcR/n^{2} )^{3} )^{1/2}

f_{cm} = (32 ϵ_{°}^{2} / Z^{2} m e^{4} × (h^{3}c^{3}R^{3}) )^{1/2} × ((1/n^{2})^{3} )^{1/2}

fcm = (32 ϵ_{°}^{2} / Z^{2} m e^{4} × (h^{3}c^{3}R^{3}) )^{1/2} × 1/n^{3} ——– (6)

As,

1/λ = R (1/m^{2} − 1/n^{2} )

put m=n−1

1/λ = R (1/( n−1)^{2} − 1/n^{2} )

Multiply both side by ”c”

c/λ = cR (n^{2} − (n−1)^{2} / n^{2} (n−1)^{2} )

c/λ = cR (n^{2} − n^{2}(1−2n) / n^{2} (n−1)^{2} )

c/λ = cR (2n−1 / n^{2} (n−1)^{2} )

f_{qm}= cR (2n−1 / n^{2} (n−1)^{2} ) ——– (7)

for n>>>1 so, eq, (7) becomes

f_{qm}≅ cR (2n) / n^{2} (n)^{2}

f_{qm}≅ 2cRn / n^{4}

f_{qm}= 2cR / n^{3} ——– (8)

### Expression for Rydberg constant:

According to the correspondence principle, for large quantum numbers, quantum frequency and classical frequency should be equal.

f_{qm} = f_{cm}

2cR / n^{3} = (32 ϵ_{°}^{2} / Z^{2} m e^{4} × (h^{3}c^{3}R^{3}) )^{1/2} × 1/n^{3}

simplify, we get,

R = m Z^{2} e^{4} / 8 ϵ_{°}^{2} h^{3}c ——– (9)

### Quantum expression for energy:

E_{n} = −hcR/n^{2}

E_{n} = −hc/n^{2} × m Z^{2} e^{4} / 8 ϵ_{°}^{2} h^{3}c

E_{n} = −m Z^{2} e^{4} / 8 ϵ_{°}^{2} h^{2} × 1/n^{2} ——– (10)

This is a quantum expression for the energy of stationary state of H-atom.

### Expression for Radii:

E =−Ze^{2} / 8πϵ_{°} r ——–from Eq.(3)

comparing with eq. (10)

−Ze^{2} / 8πϵ_{°} r = −m Z^{2} e^{4} / 8 ϵ_{°}^{2} h^{2} × 1/n^{2}

r = ϵ_{°} h^{2} / Ze^{2} πm × n^{2} OR

r = 90 n^{2}

where,

- 90 = ϵ
_{°}h^{2}/Z e^{2}πm is called Bohr’s radius. For n=1 where, 90 = 0.53 angstrum

## Atomic line spectra:

First we undersrand the concept of spectrum,

### Spectrum:

The arrangement is according to the wavelength of visible, UV, and infrared light.

### Types of the spectrum:

Continuous spectrum | Line spectrum | Band spectrum |

The spectrum in which boundary lines between colors cannot be marked and colures are diffused into each other. | The spectrum in which lines are separated by dark lines. | The molecular spectra are known as band spectrum. |

Example: Spectrum of the rainbow, Black body spectrum | Example: Atomic spectrum | ——— |

- An instrument designed for visual observation of spectrum is
**spectroscopy.** - An instrument that maps spectrum is spectroscopy.
- The study of the interaction between matter and electromagnetic radiation is called
**spectroscopy.**

### History of spectroscopy:

The History of spectroscopy began with Newton’s optics experiments (1666-1672)

- Newton applied the word
**”spectrum”**to describe the rainbow of colors that combine to form white light and that are revealed when the white light is passed through a prism.

- In 1802,
*William Hyde Wallaston*built an improved spectrometer that included a lens to focus the sun’s spectrum on a screen. Wallaston realized that color was not spread uniformly, but instead had missing patches of color, which appeared as dark bands in the spectrum.

- Later in 1815,
*German physicist Joseph Fraunhofer*also examined the solar spectrum and found about 600 such dark lines (missing colors) which are known as**Fraunhofer lines.**

**In 1666, Newton passes the white light through a prism and obtain seven colors**### Importance of spectroscopy:

Spectroscopy is a fundamental tool in the field of physics, chemistry, and astronomy. knowing the composition of atoms (different atoms show different spectrum), physical structure, and electronic structure of matter to be investigated at the atomic scale, molecule scale, macro scale, and over astronomical distances.

- It provides information not only about the arrangement and motion of the outer electrons (optical spectroscopy), but also the inner electrons( X-rays spectroscopy) and about the angular momentum, magnmeticquantum, distribution of charge and magnetism of nucleus.

- Atoms and molecules have unique spctra. As a result these spectra can be used to detect, identify and quantify information about the atoms and molecules.

### Things that are used to make spectrum:

- Ligth source
- Material
- Screen

### Types of electromagnetic radiations:

- Gamma radiation
- X-ray radiation
- UV radiation
- Visible radiation
- Infrared radiation
- Microwave radiation
- Radio waves

## Atomic line spectra:

”The spectrum of emitted radiations having specific wavelengths when current is passed through atomic gas at low pressure”

### Types of atomic line spectra:

Emission spectrum | Absorption spectrum |

The frequency of radiations emitted due to an atom making the transition from a higher energy state to a lower energy state. | The spectrums formed by the radiation they have passed through the medium lose the radiation of some certain frequency absorbed. |

### Spectral series:

The spectrum of any element has some regularities. These are classified into certain groups called spectral series.

The first series → In 1885 → Balmer series → lies in the visible region

There are three regions of the atomic spectrum of hydrogen:

- Visible region
- UV region
- Infrared region

Visible region | UV region | Infrared region |

Balmer series | Lyman series | Paschen series Bracket series Pfund series |

### Balmer formula:

λ = 364.4 n^{2} /n^{2} −4 nm

where, n= 3,4,5….

Then, the Rydberg formula arranges this formula by reciprocal it:

**1/λ = 1/364.4 × n ^{2} − 4 /n^{2} **

### Rydberg formula:

1/λ = 27**×**10^{6} [n^{2} /n^{2} − 4/n^{2}]

1/λ = 27**×**10^{6} [1 − 4/n^{2}]

1/λ = 4 **×** 27**×**10^{6} /4 [1 − 4/n^{2}]

1/λ = 1.09 **×** 10^{7} [1/4 − 1/n^{2}]

1/λ = R [1/4 − 1/n^{2}]

where R is the Rydberg constant ( 1.09 **×** 10^{7} m^{-1} )

Re-write the above formula,

**1/λ = R [1/p ^{2} − 1/n^{2}] **

where always p<n

## Energy Level Diagram for Hydrogen:

In a hydrogen atom, when an electron is move in different energy levels (from lower energy level to higher energy) it emits or absorbs energy in the form of electromagnetic radiation. (energy is quantized)

E_{n} = − 13.6/n^{2} ev

### UV- region:

#### Series: Lyman series

The series of spectral lines produced due to transitions from all energy states to the ground state is called the **Lyman series.**

1/λ = R [1/p^{2} − 1/n^{2}]

where p=1 and n=2,3,4,5….

##### when the longest wavelength is released?

The longest wavelength is released when n=2 and p=1

##### when a shorter wavelength is released?

The shorter wavelength is released when n=∞ and p=1

### Visible region:

#### Series: Balmer series

1/λ = R [1/p^{2} − 1/n^{2}]

where p=2 and n=3,4,5,6….

##### when the longest wavelength is released?

The longest wavelength is released when n=3 and p=2

##### when a shorter wavelength is released?

The shorter wavelength is released when n=∞ and p=2

### Infrared region:

#### Series: Paschen series, Bracket series, Pfund series

**Paschen series:**

The series of spectral lines produced due to transitions from all energy states to energy states E_{3} is called the **Paschen series.**

p=3 and n=4,5,6,7…..

Longest wavelength: when n=4 and p=3

Shortest wavelength: when n=∞ and p=3

**Bracket series:**

The series of spectral lines produced due to transitions from all energy states to energy states E_{4} is called the **Bracket series.**

p=4 and n=5,6,7,8…..

Longest wavelength: when n=5 and p=4

Shortest wavelength: when n=∞ and p=4

**Pfund series:**

The series of spectral lines produced due to transitions from all energy states to energy states E_{5} is called the **Pfund series.**

p=5 and n=6,7,8,9…..

Longest wavelength: when n=6 and p=5

Shortest wavelength: when n=∞ and p=5

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